Apollonius' theorem

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In elementary geometry, Apollonius' theorem is a theorem relating several elements in a triangle.

It states that given a triangle ABC, if D is any point on BC such that it divides BC in the ratio n:m (or mBD = nDC), then

mAB2 + nAC2 = mBD2 + nDC2 + (m + n)AD2.

  • When m = n( = 1), that is, AD is the median falling on BC, the theorem reduces to
AB^2 + AC^2 = BD^2 + DC^2 + 2AD^2.\,\!
  • When in addition AB = AC, that is, the triangle is isosceles, the theorem reduces to the Pythagorean theorem,
AD^2 + BD^2 = AB^2 (= AC^2).\,\!

In simpler words, in any triangle ABC\,\!, if AD\,\! is a median, then AB^2 + AC^2\,\!= 2(AD^2+BD^2)\,\! To prove this theorem, let AX\,\! be a perpendicular dropped on BC\,\! from the point A\,\!. Then, in the right-angled triangles ABX\,\! and ACX\,\!, by Pythagoras' Theorem, we have AB^2 = AX^2 + BX^2\,\!

=AX^2 + (BD+DX)^2\,\!

=AX^2 + BD^2 + DX^2 + 2.BD.DX\,\! ...........(i)

and

AC^2 = AX^2 + CX^2\,\!

=AX^2 + (CD-DX)^2\,\!

=AX^2 + CD^2 + DX^2 - 2.CD.DX\,\! ...........(ii)


Adding equations (i) and (ii),

AB^2 + AC^2\,\!

=AX^2 + BD^2 + DX^2 + 2.BD.DX + AX^2 + CD^2 + DX^2 - 2.CD.DX\,\!

=2(AX^2 + DX^2 + BD^2)\,\! {since BD=DC\,\!,thus 2.BD.DX=2.DC.DX\,\!}

=2(AX^2 + DX^2) + 2BD^2\,\!

=2(AD^2 + BD^2)\,\! {since AXD\,\! is a right angle}


And thus the theorem is proved.

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